关于EDMA的一个疑问

如果是手动触发的话，单核能否开启两个channel进行传输？我现在情况是按照例程定义了两个channel，分别映射不同的param，不同的TCC，但是当我第一次手动触发的时候，设置的传递参数是channe1，可是触发完成后发现，中断完成位确是对应的channel2的TCC。后来我发现无论我输入的是channel1 还是channel2，触发的都是channel2 param所对应的传输。。。

lester zhang：

if (CSL_edma3Init(&context) != CSL_SOK) { printf ("Error: EDMA module initialization failed\n"); }

hModule = CSL_edma3Open(&edmaObj, INSTNUM, NULL, &status); if ( (hModule == NULL) || (status != CSL_SOK)) { printf ("Error: EDMA module open failed\n"); }

chAttr.regionNum = CSL_EDMA3_REGION_GLOBAL; /*GLOBAL*/ chAttr.chaNum= 0; hChannel1 = CSL_edma3ChannelOpen(&chObj, INSTNUM, &chAttr, &status); if ((hChannel1 == NULL) || (status != CSL_SOK)) { printf ("Error: Unable to open EDMA Channel:%d\n", 0); }

chAttr.chaNum= 1; hChannel2 = CSL_edma3ChannelOpen(&chObj, INSTNUM, &chAttr, &status); if ((hChannel2 == NULL) || (status != CSL_SOK)) { printf ("Error: Unable to open EDMA Channel:%d\n", 1); }

if (CSL_edma3HwChannelSetupQue(hChannel1,CSL_EDMA3_QUE_0) != CSL_SOK) { printf ("Error: EDMA channel setup queue failed\n"); }

if (CSL_edma3HwChannelSetupQue(hChannel2,CSL_EDMA3_QUE_0) != CSL_SOK) { printf ("Error: EDMA channel setup queue failed\n"); }

CSL_edma3MapDMAChannelToParamBlock (hModule, 0, 0); CSL_edma3MapDMAChannelToParamBlock (hModule, 1, 1);

Param0= CSL_edma3GetParamHandle(hChannel1, 0, &status); if (Param0 == NULL) { printf ("Error: EDMA Get Parameter Entry failed for paramID.\n");

}

Param1= CSL_edma3GetParamHandle(hChannel2, 1, &status); if (Param1 == NULL) { printf ("Error: EDMA Get Parameter Entry failed for paramID.\n");

}

myParamSetup.option = CSL_EDMA3_OPT_MAKE(CSL_EDMA3_ITCCH_DIS, \ CSL_EDMA3_TCCH_DIS, \ CSL_EDMA3_ITCINT_DIS, \ CSL_EDMA3_TCINT_EN, \ 0, CSL_EDMA3_TCC_NORMAL,\ CSL_EDMA3_FIFOWIDTH_NONE, \ CSL_EDMA3_STATIC_DIS, \ CSL_EDMA3_SYNC_AB, \ CSL_EDMA3_ADDRMODE_INCR, \ CSL_EDMA3_ADDRMODE_INCR );

myParamSetup.srcAddr = (Uint32)DDR;//源地址 myParamSetup.aCntbCnt = CSL_EDMA3_CNT_MAKE(4,512);//因为传输的是Uint32，所以每次array跳变是4byte，一共跳变512 myParamSetup.dstAddr = (Uint32)mem;//目的地址，L2地址必须用全局地址 myParamSetup.srcDstBidx = CSL_EDMA3_BIDX_MAKE(4,4); myParamSetup.linkBcntrld= CSL_EDMA3_LINKBCNTRLD_MAKE(0xFFFF,0);//无link myParamSetup.srcDstCidx = CSL_EDMA3_CIDX_MAKE(0,1); myParamSetup.cCnt = 1;

if(CSL_edma3ParamSetup(Param0,&myParamSetup) != CSL_SOK) { printf ("Error: EDMA Parameter Entry Setup failed\n"); }

myParamSetup.option = CSL_EDMA3_OPT_MAKE(CSL_EDMA3_ITCCH_DIS, \ CSL_EDMA3_TCCH_DIS, \ CSL_EDMA3_ITCINT_DIS, \ CSL_EDMA3_TCINT_EN, \ 1, CSL_EDMA3_TCC_NORMAL,\ CSL_EDMA3_FIFOWIDTH_NONE, \ CSL_EDMA3_STATIC_DIS, \ CSL_EDMA3_SYNC_AB, \ CSL_EDMA3_ADDRMODE_INCR, \ CSL_EDMA3_ADDRMODE_INCR );

myParamSetup.srcAddr = (Uint32)mem;//源地址 myParamSetup.aCntbCnt = CSL_EDMA3_CNT_MAKE(4,512);//因为传输的是Uint32，所以每次array跳变是4byte，一共跳变512 myParamSetup.dstAddr = (Uint32)L2+ (0x10000000);//目的地址，L2地址必须用全局地址 myParamSetup.srcDstBidx = CSL_EDMA3_BIDX_MAKE(4,4); myParamSetup.linkBcntrld= CSL_EDMA3_LINKBCNTRLD_MAKE(0xFFFF,0);//无link myParamSetup.srcDstCidx = CSL_EDMA3_CIDX_MAKE(0,1); myParamSetup.cCnt = 1;

if(CSL_edma3ParamSetup(Param1,&myParamSetup) != CSL_SOK) { printf ("Error: EDMA Parameter Entry Setup failed\n"); }

regionIntr.region = CSL_EDMA3_REGION_GLOBAL; regionIntr.intr = 0x0003; //中断使能位必须和所设置的TCC相同 regionIntr.intrh = 0x0000;

CSL_edma3HwControl(hModule,CSL_EDMA3_CMD_INTR_ENABLE,&regionIntr);

regionIntr.intr = 0x0000;

CSL_edma3HwChannelControl(hChannel1,CSL_EDMA3_CMD_CHANNEL_SET,NULL);

do { CSL_edma3GetHwStatus(hModule,CSL_EDMA3_QUERY_INTRPEND,&regionIntr); } while (!(regionIntr.intr & 0x0001));//

CSL_edma3HwControl(hModule,CSL_EDMA3_CMD_INTRPEND_CLEAR,&regionIntr);

CSL_edma3HwChannelControl(hChannel1,CSL_EDMA3_CMD_CHANNEL_SET,NULL);

do { CSL_edma3GetHwStatus(hModule,CSL_EDMA3_QUERY_INTRPEND,&regionIntr); } while (!(regionIntr.intr & 0x0002));//

CSL_edma3HwControl(hModule,CSL_EDMA3_CMD_INTRPEND_CLEAR,&regionIntr);

lester zhang：

回复 lester zhang:

2楼是我的代码

lester zhang：

回复 lester zhang:

急啊

lester zhang：

回复 Andy Yin1:

感谢！！