TI中文支持网您好，我现在用VS利用pattern模式投图，我的图像是光栅图像（24bits烧进固件），我进行编写g_PatLut[0] = 0x67800;
g_PatLut[1] = 0x27804;
g_PatLut[2] = 0x27808;
g_PatLut[3] = 0x67800;
g_PatLut[4] = 0x27804;
g_PatLut[5] = 0x27808;
g_PatLut[6] = 0x67800;
g_PatLut[7] = 0x27804;
g_PatLut[8] = 0x27808;
g_PatLut[9] = 0x67800;
g_PatLut[10] = 0x27804;
g_PatLut[11] = 0x27808;
g_PatLut[12] = 0x27804;
g_PatLut[13] = 0x27808;
g_PatLut[14] = 0x67800;
g_PatLut[15] = 0x27804;
g_PatLut[16] = 0x27808;
g_PatLut[17] = 0x67800;
g_PatLut[18] = 0x27804;
g_PatLut[19] = 0x27808;
g_PatLut[20] = 0x67800;
g_PatLut[21] = 0x27804;
g_PatLut[22] = 0x27808;
g_PatLut[23] = 0x67800;
g_PatLut[24] = 0x27804;
g_PatLut[25] = 0x27808;
g_PatLut[26] = 0x67800;
g_PatLut[27] = 0x27804;
g_PatLut[28] = 0x27808;
g_PatLut[29] = 0x67800;
g_PatLut[30] = 0x27804;
g_PatLut[31] = 0x27808;
g_PatLut[32] = 0x67800;
g_PatLut[33] = 0x27804;
g_PatLut[34] = 0x27808;
g_PatLut[35] = 0x67800;
g_PatLut[36] = 0x27804;
g_PatLut[37] = 0x27808;
g_PatLut[38] = 0x67800;
g_PatLut[39] = 0x27804;
g_PatLut[40] = 0x27808;
g_PatLut[41] = 0x67800;
g_PatLut[42] = 0x27804;
g_PatLut[43] = 0x27808;
g_PatLut[44] = 0x67800;
g_PatLut[45] = 0x27804;
g_PatLut[46] = 0x27808;
g_PatLut[47] = 0x67800;
g_PatLut[48] = 0x27804;
g_PatLut[49] = 0x27808;
g_PatLut[50] = 0x67800;
g_PatLut[51] = 0x27804;
g_PatLut[52] = 0x27808;
g_PatLut[53] = 0x67800;
g_PatLut[54] = 0x27804;
g_PatLut[55] = 0x27808;
g_PatLut[56] = 0x67800;
g_PatLut[57] = 0x27804;
g_PatLut[58] = 0x27808;
g_PatLut[59] = 0x67800;
g_PatLut[60] = 0x27804;
g_PatLut[61] = 0x27808;
g_PatLut[62] = 0x67800;
g_PatLut[63] = 0x27804;
g_PatLut[64] = 0x27808;
g_PatLut[65] = 0x67800;
splashLut[0] = 0x1;
splashLut[1] = 0x2;
splashLut[2] = 0x3;
splashLut[1] = 0x4;
splashLut[4] = 0x5;
splashLut[5] = 0x6;
splashLut[6] = 0x7;
splashLut[7] = 0x8;
splashLut[8] = 0x9;
splashLut[9] = 0xA;
splashLut[10] = 0xB;
splashLut[11] = 0xC;
splashLut[12] = 0xD;
splashLut[13] = 0xE;
splashLut[14] = 0xF;
splashLut[15] = 0x10;
splashLut[16] = 0x11;
splashLut[17] = 0x12;
splashLut[18] = 0x13;
splashLut[19] = 0x14;
splashLut[20] = 0x15;
splashLut[21] = 0x16;
就是投放22张片的RGB通道的图片，请问这个图片中的三个通道的灰度信息是否一致？如果一致的话可不可以只选择
每一张图片的单通道灰度信息来代替24bits的图像灰度信息？？希望得到您的回复。GrayCode.rar
Kevin Shi：
您好！
感谢使用TI的DLP产品。
请问具体需要实现什么样的功能？不是很明白您的问题。
图片RGB通道的灰度信息是由该图片本身决定的。
谢谢
Xu Zhang：
回复 Kevin Shi:
我想要实现的功能就是把一组（24bit）的图片的光栅图像的信息完全表现投影出来，可是这个pattern模式下会有bit depth 的选项,不太理解您公司这个位深是什么意思，您能再给我解释一下一下嘛？还有DLP4500EVM中有一个插图figure4-2您能解释嘛？希望我的表述能让您明白。
Xu Zhang：
回复 Kevin Shi:
谢谢，您的解释很清楚，我做的是基于光栅投影的双目视觉，这个用pattern模式会不会对光栅信息有影响？
Kevin Shi：
回复 Xu Zhang:
您好！
在pattern模式下，图片像素和DMD的微镜之间是1对1映射的。
谢谢
