Part Number:TMS320F280021
Dear all:
在调试ADC时发现,采用定时器0 触发AD,AD进不了AD中断:
我的程序如下:
void initADC(void) { // // Setup VREF as internal // SetVREF(ADC_ADCA, ADC_INTERNAL, ADC_VREF3P3); //SetVREF(ADC_ADCA, ADC_EXTERNAL, ADC_VREF2P5); EALLOW; // // Set ADCCLK divider to /4 // AdcaRegs.ADCCTL2.bit.PRESCALE = 6; // // Set pulse positions to late // AdcaRegs.ADCCTL1.bit.INTPULSEPOS = 1; // // Power up the ADC and then delay for 1 ms // AdcaRegs.ADCCTL1.bit.ADCPWDNZ = 1; EDIS; DELAY_US(1000); } void initADCSOC(void) { // // Select the channels to convert and the end of conversion flag // EALLOW; AdcaRegs.ADCSOC0CTL.bit.CHSEL = 0; // SOC0 will convert pin A1 // 0:A0 1:A1 2:A2 3:A3 // 4:A4 5:A5 6:A6 7:A7 // 8:A8 9:A9 A:A10 B:A11 // C:A12 D:A13 E:A14 F:A15 AdcaRegs.ADCSOC0CTL.bit.ACQPS = 25; // Sample window is 10 SYSCLK cycles AdcaRegs.ADCSOC0CTL.bit.TRIGSEL = 1; //Timer0 AdcaRegs.ADCINTSEL1N2.bit.INT1SEL = 0; // End of SOC0 will set INT1 flag AdcaRegs.ADCINTSEL1N2.bit.INT1E = 1; // Enable INT1 flag AdcaRegs.ADCINTFLGCLR.bit.ADCINT1 = 1; // Make sure INT1 flag is cleared EDIS; } // // adcA1ISR - ADC A Interrupt 1 ISR // __interrupt void adcA1ISR(void) { static Uint16 *AdcBufPtr1 = Voltage1; // Pointer to ADC data buffer IOTEST=1; if((Time <= 0)||(Time > RFFT_SIZE)) { Time = 0; } else { Time--; *AdcBufPtr1++ = AdcaResultRegs.ADCRESULT0; } // // Clear the interrupt flag // AdcaRegs.ADCINTFLGCLR.bit.ADCINT1 = 1; // // Check if overflow has occurred // if(1 == AdcaRegs.ADCINTOVF.bit.ADCINT1) { AdcaRegs.ADCINTOVFCLR.bit.ADCINT1 = 1; //clear INT1 overflow flag AdcaRegs.ADCINTFLGCLR.bit.ADCINT1 = 1; //clear INT1 flag } // // Acknowledge the interrupt // PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; } void main(void) { InitSysCtrl();//100M InitGpio(); DINT; InitPieCtrl(); IER = 0x0000; IFR = 0x0000; InitPieVectTable(); EALLOW; PieVectTable.TIMER0_INT = &cpuTimer0ISR; PieVectTable.ADCA1_INT = &adcA1ISR; // Function for ADCA interrupt 1 EDIS; // // Initialize the Device Peripheral. For this example, only initialize the // Cpu Timers. // InitGpioAll(); InitCpuTimers(); ConfigCpuTimer(&CpuTimer0, 100, 2);//AD采样时间 // hans函数里面定时器中断不使能 Timer->RegsAddr->TCR.bit.TIE = 0; initADC(); initADCSOC(); IER |= M_INT1;//T0 ADCINT1 // // Enable TINT0 in the PIE: Group 1 interrupt 7 // PieCtrlRegs.PIEIER1.bit.INTx1 = 1;// ADCINT1 PieCtrlRegs.PIEIER1.bit.INTx7 = 1;//T0 // // Enable global Interrupts and higher priority real-time debug events // EINT; ERTM; while(1) {Time=RFFT_SIZE;StartCpuTimer0();//CpuTimer0Regs.TCR.bit.TSS = 0while(1){if(Time == 0){break;}StopCpuTimer0();//CpuTimer0Regs.TCR.bit.TSS = 1} }
Huit:
配置定时0时,定时器0是不进入中断的,只是采用定时器去触发AD中断,但是AD中断函数里进入不了,不知道是什么原因导致的?
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Susan Yang:
建议您使用回复框下面的“插入”功能来插入代码,以便于查看
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Huit:
void initADC(void) { // // Setup VREF as internal // SetVREF(ADC_ADCA, ADC_INTERNAL, ADC_VREF3P3); //SetVREF(ADC_ADCA, ADC_EXTERNAL, ADC_VREF2P5);EALLOW;// // Set ADCCLK divider to /4 // AdcaRegs.ADCCTL2.bit.PRESCALE = 6;// // Set pulse positions to late // AdcaRegs.ADCCTL1.bit.INTPULSEPOS = 1;// // Power up the ADC and then delay for 1 ms // AdcaRegs.ADCCTL1.bit.ADCPWDNZ = 1; EDIS;DELAY_US(1000); }void initADCSOC(void) { // // Select the channels to convert and the end of conversion flag // EALLOW; AdcaRegs.ADCSOC0CTL.bit.CHSEL = 0; // SOC0 will convert pin A1 // 0:A0 1:A1 2:A2 3:A3 // 4:A4 5:A5 6:A6 7:A7 // 8:A8 9:A9 A:A10 B:A11 // C:A12 D:A13 E:A14 F:A15 AdcaRegs.ADCSOC0CTL.bit.ACQPS = 25; // Sample window is 10 SYSCLK cyclesAdcaRegs.ADCSOC0CTL.bit.TRIGSEL = 1; //Timer0AdcaRegs.ADCINTSEL1N2.bit.INT1SEL = 0; // End of SOC0 will set INT1 flag AdcaRegs.ADCINTSEL1N2.bit.INT1E = 1; // Enable INT1 flag AdcaRegs.ADCINTFLGCLR.bit.ADCINT1 = 1; // Make sure INT1 flag is clearedEDIS; }// // adcA1ISR - ADC A Interrupt 1 ISR // __interrupt void adcA1ISR(void) { static Uint16 *AdcBufPtr1 = Voltage1; // Pointer to ADC data bufferIOTEST=1;if((Time <= 0)||(Time > RFFT_SIZE)) { Time = 0; } else { Time--; *AdcBufPtr1++ = AdcaResultRegs.ADCRESULT0; } // // Clear the interrupt flag // AdcaRegs.ADCINTFLGCLR.bit.ADCINT1 = 1;// // Check if overflow has occurred // if(1 == AdcaRegs.ADCINTOVF.bit.ADCINT1) { AdcaRegs.ADCINTOVFCLR.bit.ADCINT1 = 1; //clear INT1 overflow flag AdcaRegs.ADCINTFLGCLR.bit.ADCINT1 = 1; //clear INT1 flag }// // Acknowledge the interrupt // PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;}void main(void) { InitSysCtrl();//100MInitGpio();DINT;InitPieCtrl();IER = 0x0000; IFR = 0x0000;InitPieVectTable();EALLOW; PieVectTable.TIMER0_INT = &cpuTimer0ISR;PieVectTable.ADCA1_INT = &adcA1ISR; // Function for ADCA interrupt 1EDIS; // // Initialize the Device Peripheral. For this example, only initialize the // Cpu Timers. //InitGpioAll();InitCpuTimers();ConfigCpuTimer(&CpuTimer0, 100, 2);//AD采样时间// hans函数里面定时器中断不使能Timer->RegsAddr->TCR.bit.TIE = 0;initADC();initADCSOC();IER |= M_INT1;//T0 ADCINT1// // Enable TINT0 in the PIE: Group 1 interrupt 7 // PieCtrlRegs.PIEIER1.bit.INTx1 = 1;// ADCINT1 PieCtrlRegs.PIEIER1.bit.INTx7 = 1;//T0// // Enable global Interrupts and higher priority real-time debug events // EINT; ERTM;while(1) {Time=RFFT_SIZE;StartCpuTimer0();//CpuTimer0Regs.TCR.bit.TSS = 0while(1){if(Time == 0){break;}StopCpuTimer0();//CpuTimer0Regs.TCR.bit.TSS = 1}代码如上
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Susan Yang:
抱歉,还没来得及测试。请问您是解决问题了?