请教一个mmwave里面的dma传输的问题

config.paramSetConfig.aCount = aCount;

   config.paramSetConfig.bCount = bCount;

   config.paramSetConfig.cCount = 1U;

   config.paramSetConfig.bCountReload = 0U;

   config.paramSetConfig.sourceBindex = srcBIdx;

   config.paramSetConfig.destinationBindex = dstBIdx;

   config.paramSetConfig.sourceCindex = 0U;

   config.paramSetConfig.destinationCindex = 0U;

   config.paramSetConfig.linkAddress = EDMA_NULL_LINK_ADDRESS;

   config.paramSetConfig.transferType = (uint8_t)EDMA3_SYNC_A;

对于这样一个sync a的dma如果bcount的赋值为2那么当调用一次这个dma时候回传输2个aCount大小的array，还是每次只会传输一个aCount大小的array?

user5790532：

config.paramSetConfig.aCount = sampleLenInBytes;config.paramSetConfig.bCount = numRangeBins;config.paramSetConfig.cCount = (uint16_t) numRxAnt;config.paramSetConfig.bCountReload = 0U;
config.paramSetConfig.sourceBindex = (int16_t) sampleLenInBytes;config.paramSetConfig.destinationBindex = (int16_t)(numDopplerBins * numTxAnt * numRxAnt * sampleLenInBytes);
config.paramSetConfig.sourceCindex = (int16_t)(numRangeBins * sampleLenInBytes);config.paramSetConfig.destinationCindex = (int16_t)(numDopplerBins * sampleLenInBytes);
config.paramSetConfig.linkAddress = EDMA_NULL_LINK_ADDRESS;config.paramSetConfig.transferType = (uint8_t)EDMA3_SYNC_AB;
同样对于sync ab 类型的 每次调用是传输1个aCount*bCount的数据还是cCount个？